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1)
Two masses connected by a string
b
draw 2 free body diagrams (one for each mass).
String is massless
b
tension
T
is same on both ends of the string:
T
N
m
1
g
F
x
a
θ
m
2
g
T
x
a
Netforce:
F
net2
= m
2
g
+
T
Magnitude of netforce: F
net2
= m
2
g – T
Newton 2
nd
law: F
net
= ma
b
m
2
g – T = m
2
a
T = m
2
(g – a)
Netforce:
F
net1
=
T
+ m
1
g
+
N
+
F
Magnitude of netforce:
F
net1
= T  m
1
g(sin
θ
+
μ
K
cos
θ
)
Newton 2
nd
law: F
net
= ma
T  m
1
g(sin
θ
+
μ
K
cos
θ
) = m
1
a
Combining the two equations above yields:
m
1
= m
2
(g – a) / [a + g(sin
θ
+
μ
K
cos
θ
)]
2)
The netforce on the ball is F
net
= T – mg = ma = m v
2
/ R (centripetal acceleration)
b
T =
mg+mv
2
/R = m(g + v
2
/ R)
3)
Normal force is normal to the plane, pointing upwards from the plane.
The magnitude ‘N’ of the normal force is N = mg·cos
θ
4)
Friction is along the slope and in the opposite direction of the motion. The magnitude is
F =
μ
N =
μ
·m·g·cos
θ
5)
Along the incline: mg·sin
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This note was uploaded on 11/07/2010 for the course PHYS 1120 taught by Professor Rogers during the Spring '08 term at Colorado.
 Spring '08
 ROGERS
 Physics, Force, Mass

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