capa14 - is the sum of the pressure due to the weight of...

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CAPA set 14 1) 1 m 3 = (100 cm) 3 = 10 6 cm 3 b 10 6 cm 3 · 1gr/cm 3 = 10 6 gr = 1000 kg 2) mass flow rate = mass flowing out / time. mass = volume * density. Density of water: 1000 kg / m 3 3) The particles (or fields) in a transverse wave oscillate in a direction perpendicular to the direction of wave motion. In longitudinal waves, the particles move parallel to the direction of wave motion. Electromagnetic waves are transverse waves. 4) Draw a free body diagram. Find the component of the force ‘mg’ along the plane: F H = mg·sin θ In equilibrium this force will have to be canceled by the force exerted by the spring: 0 = F net = mg·sin θ - kx b kx = mg·sin θ b x = (mg·sin θ )/k 5) Flight time: x = vt b t = x/v Vertical drop during the flight time: h = ½ g t 2 = ½ g (x/v) 2 6) At the top, the net-force on the ball is F net = F Tension + mg = m v 2 /R (circular motion) b F Tension = m v 2 /R – mg 7) The force on the door is equal to the pressure times the area of the door. The pressure
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Unformatted text preview: is the sum of the pressure due to the weight of the water plus the atmospheric pressure pushing on the surface of the water. F from_outside = (h·g· ρ water + p atmosphere )·A Door 8) F from_inside = p atmosphere ·A Door 9) Conservation of energy: ½ m v y 2 = mgh b v y 2 = 2gh v = sqrt(v x 2 +v y 2 ) = sqrt(v x 2 +2gh) ; sqrt: ‘square root’ h y x v x v y v h v x 10) At maximum load: F net = 0 = F Buoancy – g( m Balloon + m Helium + m cargo ) b m cargo = F Buoancy /g - m Balloon – m Helium The bouyant force is equal to the weight of the displaced air: F Buoancy = V Baloon · ρ Air = 4/3 π r 3 m Helium = V Baloon · ρ Helium 11-13) y = A · sin(kx – ω t) k = 2 π / λ , λ : ‘wavelength’ ω = 2 π /T , T 0 : ‘Period’ 14) v y = dy/dt = -A· ω ·cos(kx – ω t) b max vertical speed: v y,max = A· ω...
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This note was uploaded on 11/07/2010 for the course PHYS 1120 taught by Professor Rogers during the Spring '08 term at Colorado.

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capa14 - is the sum of the pressure due to the weight of...

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