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2010%20BRAE%20236%20HW10

2010%20BRAE%20236%20HW10 - To calculate this we must...

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BRAE 236 - HW10 Given: In the sketch below, static lift = 120 feet, drawdown = 15 feet, pump bowls set at 180 feet Discharge pressure = 45 psi Column and Discharge Head losses = 5 psi Find: a) TDH - Total Dynamic Head b) WHP at Q = 225 GPM Formulas: TDH of a Well Pump = Static Lift + Drawdown + Surface Discharge Pressure + Column and Discharge Head Losses WHP = Q * TDH / 3960 Solution: Q = 225 GPM Static Lift = 120 ft Drawdown = 15 ft Discharge Pressure = 45 psi Column and Discharge Head Losses = 5 psi a) TDH = 120 ft + 15 ft + 45 psi + 5 psi =
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Unformatted text preview: To calculate this we must convert psi into ft --> 2.31 ft = 1 psi Discharge Pressure = 45 psi ==> 45 psi x 2.31ft/1psi = 103.95 ft Column and Discharge Head Losses = 5 psi ==> 5 psi x 2.31ft/1psi = 11.55 ft TDH = 120 ft + 15 ft + 103.95 ft + 11.55 = 250.5 ft b) WHP = 225 GPM x 250.5 ft / 3960 = 14.233 hp Answer: a) 251ft b) 14.2hp Discharge Pressure Static Lift Drawdown Ground Surface Well Casing Column Pipe Pump Bowls Discharge Head Motor Static Water Level...
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