HW7-Solution

# HW7-Solution - B M a 63.600 in a F.25 lb(cos 25 sin 25 i k...

This preview shows pages 1–4. Sign up to view the full content.

HW7 - Solution Terry Cooke: Cal Poly San Luis Obispo

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Chapter 3, Solution 85 ( a ) Equivalence requires : or 250 N F F P F 60° : (0.3 m)(250 N) 75 N m B M     M The equivalent force-couple system at B is 250 N F 60° 75.0 N m M ( b ) Require Equivalence then requires : 0 cos cos x A B F F F or cos 0 A B F F   : 250 sin sin y A B F F F   Now if 250 0 A B F F     reject cos 0 or 90 and 250 A B F F Also : (0.3 m)(250 N) (0.2m) B A M F or 375 N A F   and 625 N B F 375 N A F 60 625 N B F 60
Chapter 3, Solution 89 Since the forces at A and B are parallel, the force at B can be replaced with the sum of two forces with one of the forces equal in magnitude to the force at A except with an opposite sense, resulting in a force-couple. Have 2.9 lb 2.65 lb 0.25 lb, B F where the 2.65 lb force be part of the couple. Combining the two parallel forces, couple (2.65 lb)[(3.2 in. 2.8 in.)cos25 ] 14.4103 lb in. M and couple 14.4103 lb in. M A single equivalent force will be located in the negative z -direction Based on : 14.4103 lb in. [(.25 lb)cos 25 ]( )

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: B M a 63.600 in. a F (.25 lb)(cos 25 sin 25 ) i k F (0.227 lb) (0.1057 lb) i k and is applied on an extension of handle BD at a distance of 63.6 in. to the right of B Chapter 3, Solution 97 Equivalence requires : (150 N)( cos 35 sin 35 ) (122.873 N) (86.036 N) F F j k j k / : A D A M M r F where / (0.18 m) (0.12 m) (0.1 m) D A r i j k Then 0.18 0.12 0.1 N m 122.873 86.036 [( 0.12)( 86.036) (0.1)( 122.873)] [ (0.18)( 86.036)] [(0.18)( 122.873)] (22.6 N m) (15.49 N m) (22.1 N m) i j k M i j k i j k The equivalent force-couple system at A is (122.9 N) (86.0 N) F j k (22.6 N m) (15.49 N m) (22.1 N m) M i j k...
View Full Document

{[ snackBarMessage ]}

### Page1 / 4

HW7-Solution - B M a 63.600 in a F.25 lb(cos 25 sin 25 i k...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online