HW9-Solution

744 t sin13996 t 024185 t t 72 lb b sin13996 sin10626

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Unformatted text preview: b B sin13.996 sin106.26 (T 72 lb)(sin 59.744°) (T 72)(0.86378) T 100.0 lb 100.00 lb B sin 106.26° sin 59.744 111.14 lb (100 lb) B 111.1 lb 30.3 Chapter 4, Solution 85 (a) As shown in the free-body diagram of the slender rod AB, the three forces intersect at C. From the geometry of the forces Free-Body Diagram: tan xCB yBC 1 L sin 2 where xCB and yBC tan L cos 1 tan 2 2 tan 30 or For tan tan 2 tan 30 1.15470 49.107 or 78.480 N 49.1 (b) From force triangle W mg (8 kg)(9.81 m/s 2 ) A W tan (78.480 N) tan 30 45.310 N or 90.621 N A 45.3 N 60.0 and B W cos 78.480 N cos 30 or B 90.6 N...
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This note was uploaded on 11/07/2010 for the course ME 211 taught by Professor Staff during the Fall '05 term at Cal Poly.

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