HW9-Solution

# 744 t sin13996 t 024185 t t 72 lb b sin13996 sin10626

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: b B sin13.996 sin106.26 (T 72 lb)(sin 59.744°) (T 72)(0.86378) T 100.0 lb 100.00 lb B sin 106.26° sin 59.744 111.14 lb (100 lb) B 111.1 lb 30.3 Chapter 4, Solution 85 (a) As shown in the free-body diagram of the slender rod AB, the three forces intersect at C. From the geometry of the forces Free-Body Diagram: tan xCB yBC 1 L sin 2 where xCB and yBC tan L cos 1 tan 2 2 tan 30 or For tan tan 2 tan 30 1.15470 49.107 or 78.480 N 49.1 (b) From force triangle W mg (8 kg)(9.81 m/s 2 ) A W tan (78.480 N) tan 30 45.310 N or 90.621 N A 45.3 N 60.0 and B W cos 78.480 N cos 30 or B 90.6 N...
View Full Document

## This note was uploaded on 11/07/2010 for the course ME 211 taught by Professor Staff during the Fall '05 term at Cal Poly.

Ask a homework question - tutors are online