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Unformatted text preview: vu (tv2894) – Homework 4 (Quest) – miner – (55096) 1 This printout should have 6 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 10.0 points If the function f is continuous everywhere and f ( x ) = x 2 − 25 x + 5 when x negationslash = − 5, find the value of f ( − 5). 1. f ( − 5) = − 10 correct 2. f ( − 5) = − 5 3. f ( − 5) = − 25 4. f ( − 5) = 10 5. f ( − 5) = 25 6. f ( − 5) = 5 Explanation: Since f is continuous at x = − 5, f ( − 5) = lim x → 5 f ( x ) . But, after factorization, x 2 − 25 x + 5 = ( x − 5)( x + 5) x + 5 = x − 5 , whenever x negationslash = − 5. Thus f ( x ) = x − 5 for all x negationslash = − 5. Consequently, f ( − 5) = lim x → 5 ( x − 5) = − 10 . 002 10.0 points Determine which of the following could be the graph of f near the origin when f ( x ) = x 2 − 7 x + 10 2 − x , x negationslash = 2 , 4 , x = 2 . 1. 2....
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 Fall '10
 Gualdini
 Calculus, lim, Continuous function

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