This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: vu (tv2894) Homework 16 (Section 4.4) miner (55096) 1 This printout should have 4 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 10.0 points Determine if lim x x 3 5 x 2 x 3 + x 2 + 1 exists, and if it does, find its value. 1. limit = 3 2 2. limit = 0 3. limit = 1 2 correct 4. limit = 1 5. limit = 1 2 6. limit does not exist Explanation: After division by x 3 in both the numerator and denominator, we see that x 3 5 x 2 x 3 x 2 + 1 = 1 5 x 2 2 + 1 x + 1 x 3 . On the other hand, lim x parenleftBig 1 5 x 2 parenrightBig = 1 , while lim x parenleftBig 2 + 1 x + 1 x 3 parenrightBig = 2 . Consequently, lim x x 3 5 x 2 x 3 + x 2 + 1 exists and limit = 1 2 . 002 10.0 points A certain function f is known to have the properties lim x f ( x ) = 6 , lim x f ( x ) = 4 ....
View
Full
Document
This note was uploaded on 11/07/2010 for the course M 408N taught by Professor Gualdini during the Fall '10 term at University of Texas at Austin.
 Fall '10
 Gualdini
 Calculus

Click to edit the document details