Homework 16 - vu (tv2894) Homework 16 (Section 4.4) miner...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: vu (tv2894) Homework 16 (Section 4.4) miner (55096) 1 This print-out should have 4 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points Determine if lim x x 3- 5 x 2 x 3 + x 2 + 1 exists, and if it does, find its value. 1. limit = 3 2 2. limit = 0 3. limit = 1 2 correct 4. limit = 1 5. limit =- 1 2 6. limit does not exist Explanation: After division by x 3 in both the numerator and denominator, we see that x 3- 5 x 2 x 3- x 2 + 1 = 1- 5 x 2 2 + 1 x + 1 x 3 . On the other hand, lim x parenleftBig 1- 5 x 2 parenrightBig = 1 , while lim x parenleftBig 2 + 1 x + 1 x 3 parenrightBig = 2 . Consequently, lim x x 3- 5 x 2 x 3 + x 2 + 1 exists and limit = 1 2 . 002 10.0 points A certain function f is known to have the properties lim x f ( x ) = 6 , lim x f ( x ) = 4 ....
View Full Document

This note was uploaded on 11/07/2010 for the course M 408N taught by Professor Gualdini during the Fall '10 term at University of Texas at Austin.

Page1 / 3

Homework 16 - vu (tv2894) Homework 16 (Section 4.4) miner...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online