homework_9_correct

# homework_9_correct - .115 I 3.028.1 J 5.046.142 K 2.019.075...

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1. Plot 3 has the greatest species richness because it has the greatest number (6) of species out of the three communities. 2. Plot 1 Species Abundance p i p i lnp i A 80 .91 -.086 B 2 .02 -.078 C 2 .02 -.078 D 2 .02 -.078 E 2 .02 -.078 H’= .398 Plot 2 Species Abundance p i p i lnp i C 25 .25 -.347 D 25 .25 -.347 E 25 .25 -.347 F 25 .25 -.347 H’= 1.388 Plot 3 Species Abundance p i p i lnp i G 90 .833 -.152 H 4 .037

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Unformatted text preview: -.115 I 3 .028-.1 J 5 .046-.142 K 2 .019-.075 L 4 .037-.122 H’= .706 3. Evenness for both plots= Plot 1: .398/1.61= .247 Plot 2: 1.388/1.388= 1 Plot 3: .706/1.794= .394 4. Pair Similarity (C s ) Dissimilarity (D) 1 and 2 1.125-.125 1 and 3 1 2 and 3 1 Mean dissimilarity: .625 5....
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homework_9_correct - .115 I 3.028.1 J 5.046.142 K 2.019.075...

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