This preview shows page 1. Sign up to view the full content.
Section 6.1
167
and so
890 = 750 + 400 + 100 + 50 
328 
25 
12 
35  8 
33
+ 17 + 4 + 9 + 2
10
nAn G n
01·
Thus,
10
01
=
891 890 = 1.
(b) We want
IG" (0
u
A
u
e)l,
and we know
Ie" (0 u
A
u e)1
=
IGIIG n (0 u
A
u e)1
=
100
IG n (0 u
A
u e)l·
Now
G n (0 u
A
u e)
=
(G n 0) u (G n
A)
u (G n e)
and so
IGn (0 uAue)1
=
IGn 01
+ IGnAI +
IGnelIGn 0
nAIIGnOnel
IG n
B
n
+
IG
nOn
A
n
=
25 + 35 + 33 
17  9  2 + 1
=
66
So the number we want is 100 
66
=
34.
(c) There are six possibilities to consider. The number who bought orange juice and apple juice but
no other kind of juice is
1(0 n
A)
" (G u e)1
=
10 n
AII(O n
n (G u e)1
=
10 n
AII(O
nAn G) u (0
nAn e)1
=
10nAIIOnAnGIIOnAnCi
+
10nAnGnei
=
328 
17  4 + 1
=
308.
Similarly, the number who bought orange juice and grapefruit juice but no other kind of juice is
2517
9+1
=
O. The number who bought only orange juice and citrus punch is
1249+1
=
O. The number who bought only apple juice and grapefruit juice is 35 
17  2 + 1
=
17. The
number who bought only apple juice and citrus punch is 8  4  2
+
1
=
3. The number who
bought only grapefruit juice and citrus punch is 33  2  9 + 1 = 23. Thus, we conclude that
This is the end of the preview. Sign up
to
access the rest of the document.
 Summer '10
 any
 Graph Theory

Click to edit the document details