Unformatted text preview: (b) ]6 = l2Â· (c) Since the possibilities are (1,2), (2,3), (3,4), (4,5), (5,6) and their reverses, the answer is ~~ = 5 18Â· (d) There are 3 x 3 = 9 cases where the odd number is first and 9 more where the even number is fi Th . 18 1 rst. e answer IS 36 = "2. 2. (a)~; (b) ~ 1Â· 6 3' (e) Since the only possible number is 3, the answer is i. 3. (a) 3~ (b) The complement of this event is {(5, 6), (6,5), (6, 6)}, so the answer is 133 6 = g. (c) 70 = 2 x 5 x 7. The possibilities are (1, 1), (1,2), (1,5), (2,5) and their reverses. The answer is 3~. (d) The possible sums are 5 and 10. The answer is W = ;6. 4. (a) The only possibility is (5,5,5), so the answer is 2~6. (b) The complement of the event is {(6, 6, 5), (6,5,6), (5,6,6), (6,6, 6)}, so the answer is 12f6 = 53 54Â· (c) The prime numbers which can appear are 2, 3, 5, and these can be arranged in 3! ways. Th . 6 1 e answer IS 216 = 36Â· (d) ~~~~: = ~....
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 Summer '10
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 Graph Theory, Prime number, ways, AdditionÂ Rule

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