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Unformatted text preview: An B is the event "the total is eight or nine," so P(A n B) = tt = ~, Also, P(A) = 5t4+3+21 =. ..Q. . andP(B) = 1~ =.. SoP(AI B) = p(AnB) = l 36 12 36 6' P(B) 10' (b) P(B I A) = P(B n A) = ~ P(A) 5' (c) An C is the event "the total is nine or eleven," so P(A n C) = W = ~, Also P(C) = ~, so P(A I C) = P(A n C) = ! P(C) 3' (d) P(C I A) = P(C n A) = ~ P(A) 5' (e) BnC is the event "the total is 3, 5, 7, or 9, soP(BnC) = ~~ = ~andP(BIC) = (P~~)C) = 8 g' (t) P(C I B) = P( C n B) = ~ P(B) 15' p~nB) ...Q. . ...Q. . 11. [BB] An B is the event "a 6 appears," So P(A I B) = P(B) = 2i = ~, and P(B I A) = ~ = 24 2 1 5 2' AandBarenotindependentbecauseP(A)P(B) = ~(;4) = 18 whileP(AnB) = 2~' A and B are not mutually exclusive because A n B =f 0,...
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 Summer '10
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 Graph Theory

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