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Unformatted text preview: = 7, R = 8, N = 26, V E + R = 7 13 + 8 = 2, N = 26 :::; 26 = 2E and E = 13 :::; 15 = 3V  6. 2. (a) This is not planar. The graph is homeomorphic to lC 5 ("removing" the two vertices of degree 2). (b) This is not planar. Labeling the graph as shown, the subgraph obtained by removing edges BH, CD and D H is homeomorphic to lC3,3: the bipartition sets are {B,E,G} and {C,D,F}, with vertices A and H "removed". (c) The graph is planar, as shown. A (d) The graph contains a subgraph homeomorphic to lC3,3 as shown. Deleting the edges shown with dotted lines gives the sub graph. What remains would be lC 3,3 except for the additional vertex at G. G I c '_7"'D E c E H D A B c...
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This note was uploaded on 11/08/2010 for the course MATH discrete m taught by Professor Any during the Summer '10 term at FSU.
 Summer '10
 any
 Graph Theory, Sets

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