HW 3 Ideal Gases - roberts (eer474) – Homework 3: Ideal...

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Unformatted text preview: roberts (eer474) – Homework 3: Ideal gases – Shear – (52375) 1 This print-out should have 12 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. You may need to look up conversion factors and values of R in the back of your textbook. 001 (part 1 of 3) 10.0 points Methanol (CH 3 OH) is the simplest of the al- cohols. It is synthesized by the reaction of hydrogen and carbon monoxide: CO(g) + 2 H 2 (g)-→ CH 3 OH If 559 mol of CO and 481 mol of H 2 are present, which is the limiting reactant? 1. H 2 correct 2. CO Explanation: n CO = 559 mol n H 2 = 481 mol limiting reactant = ? mole ratio : 2 mol H 2 1 mol CO . n H 2 required = 559 molCO × 2 mol H 2 1 mol CO = 1118 mol H 2 Because there is only 481 mol H 2 available, the limiting reactant is H 2 . 002 (part 2 of 3) 10.0 points How much of the excess reactant remains un- changed? Correct answer: 318 . 5 mol. Explanation: remaining excess reactant = ? n CO reacting = 1 mol CO 2 mol H 2 × 481 mol H 2 = 240 . 5 mol CO n excessreactant = 559 mol CO- 240 . 5 mol CO = 318 . 5 mol CO 003 (part 3 of 3) 10.0 points How much CH 3 OH is formed? Correct answer: 240 . 5 mol. Explanation: n limiting reactant = 481 mol H 2 amounts of CH 3 OH = ? mole ratio : 1 mol CH 3 OH 2 mol H 2 n CH 3 OH = 1 mol CH 3 OH 2 mol H 2 × 481 mol H 2 = 240 . 5 mol CH 3 OH 004 10.0 points Helium is used to inflate football-shaped bal- loons that will be released in Memorial sta- dium for the opening game of the football...
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This note was uploaded on 11/08/2010 for the course CHEM 301 taught by Professor Wandelt during the Spring '08 term at University of Texas.

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HW 3 Ideal Gases - roberts (eer474) – Homework 3: Ideal...

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