Exam 3 - Version 112 Exam Three: Shear Shear (52375) 1 This...

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Unformatted text preview: Version 112 Exam Three: Shear Shear (52375) 1 This print-out should have 27 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. DrRuth says: In all cases, select the answer that BEST answers the question asked. The total number of points on this exam is 350. Read the whole thing first and plan which to answer first because you feel confident about them. Notice the harder ones and save them up till last so you dont use up all your time working on them. Unless otherwise stated, assume the gases in all questions are ideal. Shear 52375 g = 9 . 8 m / s 2 1 atm = 101325 Pa = 760 torr R = 0.08206 L atm K 1 mol 1 R = 0.08314 L bar K 1 mol 1 R = 8.314 J K 1 mol 1 Effusion rate of gas 1 Effusion rate of gas 2 = radicalbigg M 2 M 1 Effusion rate at T 1 Effusion rate at T 2 = radicalbigg T 1 T 2 KE = 2 / 3 RT u rms = radicalbigg 3 RT M 001 20.0 points DrRuth says: First balance the reaction equa- tion. For the reaction ? C 6 H 6 + ? O 2 ? CO 2 + ? H 2 O 42 . 1 grams of C 6 H 6 are mixed with 112 . 9 grams of O 2 and allowed to react. How much CO 2 could be produced by this reaction? 1. 124 . 2 g correct 2. 108 . 4 g 3. 192 . 5 g 4. 234 . 7 g 5. 260 . 8 g 6. 165 . 2 g 7. 142 . 3 g 8. 88 . 71 g 9. 99 . 36 g 10. 155 . 2 g Explanation: m C 6 H 6 = 42 . 1 g m O 2 = 112 . 9 g The balanced equation is 2 C 6 H 6 + 15 O 2 12 CO 2 + 6 H 2 O . The molecular weight of C 6 H 6 is 78 . 1118 g/mol, giving 0 . 538971 mol C 6 H 6 . The molecular weight of O 2 is 31 . 9988 g/mol, giving 3 . 52826 mol O 2 . . 538971 mol C 6 H 6 15 mol O 2 2 mol C 6 H 6 = 4 . 04228 mol O 2 , which is more than what is actually present. Therefore the limiting reactant must be O 2 . The molecular weight of CO 2 is 44 . 0095 g/mol. The limiting reactant (O 2 ) will yield 2 . 82261 mol CO 2 which is equal to 124 . 2 g of CO 2 . . 538971 mol C 6 H 6 12 mol CO 2 2 mol C 6 H 6 44 . 0095 g CO 2 1 mol CO 2 = 124 . 2 g CO 2 002 10.0 points What types of intermolecular interactions does chloroform (CH 3 Cl) exhibit? I) London dispersion II) dipole-dipole III) hydrogen bonding IV) covalent bonding Recall that chloroform is tetrahedral elctronic geometry with C as the central atom. Version 112 Exam Three: Shear Shear (52375) 2 1. I and II only correct 2. II and III only 3. I, II, and III only 4. II and IV only 5. II only Explanation: All molecules, because they have elec- tron clouds, experience instantaneous dipoles. CH 3 Cl is polar and thus experiences dipole- dipole interactions. CH 3 Cl does not contain any O H, N H, or F H bonds and therefore does not experience any hydrogen bonding interactions. Covalent bonding is an intramolecular interaction....
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This note was uploaded on 11/08/2010 for the course CHEM 301 taught by Professor Wandelt during the Spring '08 term at University of Texas at Austin.

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Exam 3 - Version 112 Exam Three: Shear Shear (52375) 1 This...

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