answer - 1-5This is a case of dilation. =TT in this problem...

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Unformatted text preview: 1-5This is a case of dilation. =TT in this problem with the proper time =TT( 29-=-=-1 21 22211TvvTTccT;in this case =2TT, ( 29=-=-1 221 221114LvL therefore =0.866vc.1-6This is a case of length contraction. =LL in this problem the proper length =LL, -=-=-1 21 222211vLLLvcLc; in this case =2LL, ( 29=-=-1 221 221114LvL therefore =0.866vc.1-8=LL( 29(29==-=-=-=1 2221 21 2221175110.661100LvLcLvcccL1-9=earthLL=-1 22earth21vLLc, L, the proper length so (29==-=1 22earth10.90.436LLLL.1-20(29 (29++===++220.900.700.98110.900.70vuccucvu ccc c1-21(29 (29--=== ---220.500.800.50110.500.80XXXuvccucu v ccc c2-1(29=-1 2221mvpvc(a)(29(29(29--==-27211 221.67 10 kg0.015.01 10 kg m s10.01cpc c(b)(29(29(29--==-27191 221.67 10 kg0.52.89 10 kg m s10.5cpc c(c)(29(29(29--==-27181 221.67 10 kg0.91.03 10 kg m s10.9cpc c(d)--==132281.00 MeV1.602 10 J5.34 10 kg m s2.998 10 m sc so for (a) (29(29--==21225.01 10 kg m s100 MeV9.38 MeV5.34 10 kg m scpcSimilarly, for (b) =540 MeVpc and for (c) =1 930 MeVpc.2-2(a)Scalar equations can be considered in this case because relativistic and classical velocities are in the same direction.(29(29(29=====---=1 221 21 222111.901.9011.90110.85mvpmvmvvcv cv cc(b)No change, because the masses cancel each other....
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answer - 1-5This is a case of dilation. =TT in this problem...

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