physics 111 hw1

# physics 111 hw1 - sindt(as53996 – HW 1 – Opyrchal...

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Unformatted text preview: sindt (as53996) – HW 1 – Opyrchal – (11101) 1 This print-out should have 9 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points A basketball player is 6 ft 10 5 8 in tall. What is his height in centimeters? Correct answer: 209 . 868 cm. Explanation: We can convert to inches and then to cen- timeters: 6 ft 10 5 8 in = parenleftbigg 6 ft · 12 in 1 ft + 10 . 625 in parenrightbigg × 2 . 54 cm 1 in = 209 . 868 cm . 002 10.0 points For the given triangles, a = 10 . 1 m, b = 7 . 45 m, and α = 56 . 8 ◦ . a b α θ Find θ . Correct answer: 28 . 8611 ◦ . Explanation: Let the common side be x . a b x α θ In the triangle on the left, tan α = x a x = a tan α , and in the triangle on the right, sin θ = b x = b a tan α θ = arcsin parenleftbigg b a tan α parenrightbigg = arcsin bracketleftbigg 7 . 45 m (10 . 1 m) tan 56 . 8 ◦ bracketrightbigg = 28 . 8611 ◦ . 003 10.0 points A person walks 45 m East and then walks 33 m at an angle 38 ◦ North of East. What is the magnitude of the total dis- placement? Correct answer: 73 . 8539 m. Explanation: Let : R a = 45 m , R b = 33 m , and θ = 38 ◦ . The total displacement is the vector sum of the two displacements, so R x = R a + R b cos θ = 45 m + (33 m) cos38 ◦ = 71 . 0044 m and R y = R b...
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physics 111 hw1 - sindt(as53996 – HW 1 – Opyrchal...

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