M3 Procedure to determine F3in section V.2 and V.3 Refer to fig.1. We know the directions of 1FGand 2FG. The vector 21FFGG+lies somewhere within the angle φdefined by 1FGand 2FG. Since 0321=++FFFGGG→213FFFGGG−−=. Thus 3FGlies somewhere within the arc AB. The following procedure can be followed to find both magnitude and direction of 3FGStep 1.Load the first and second hangers with m1and m2. Leave the third hanger empty for the time being. Pull down on the string of the third hanger so that the ring is approximately centered around the peg P. Step 2. Scan the position of the third pulley within the arc AB. At some specific position of the pulley within the arc AB the ring will move with respect to the peg P. This defines the angle θ3. Now load the third hanger with a test mass. One of the following two distinct outcomes will occur: Outcome A(see fig. 2a).
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