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Unformatted text preview: The atomic weight of boron is 10.811 amu. The masses of the two naturally occurring isotopes 5 10 B and 5 11 B, are 10.013 and 11.009 amu, respectively. Calculate the fraction and percentage of each isotope. 10.811 amu = {(x)(10.013)} + {(1x)(11.099)} amu = (10.013x + 11.009  11.009x) amu0.198 amu = 0.996x so x = 0.199 i.e., the B10 is 19.9% and the B11 is 80.1% POINT OUT LOGIC!!...
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 Fall '07
 Fakhreddine/Lyon

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