CH13 Notes Part 4 Example Worksheets Answers

CH13 Notes Part 4 Example Worksheets Answers - Beryllium...

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Oxygen, O 2 Valence e = 2x6 = 12 O O No central atom, so LINEAR NON POLAR covalent bond; NON POLAR molecule Beryllium Dichloride BeCl 2 Valence e = 2 + (2x7) = 16 RHED = 2 Electronic geometry = LINEAR. No lone pairs on Be Molecular geometry = LINEAR Be Cl Cl δ - δ + δ - POLAR covalent bonds; NON POLAR molecule 180° Boron Trichloride, BCl 3 Valence e = 3 + (3x7) = 24 B Cl Cl Cl RHED = 3 Electronic geometry = TRIGONAL PLANAR. No lone pairs on B Molecular geometry = TRIGONAL PLANAR POLAR covalent bonds; NON POLAR molecule 120° 1 2 0 ° Methane , CH 4 Valence e = 4 + (4x1) = 8 C H H H H RHED = 4 Electronic geometry = TETRAHEDRAL. No lone pairs on C Molecular geometry = TETRAHEDRAL Very slightly POLAR covalent bonds; NON POLAR molecule C H H H H REDRAW!! ALL ANGLES 109.5°
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Ammonium Ion , NH 4 + Valence e = 5+(4x1)-1 = 8 RHED = 4 Electronic geometry = TETRAHEDRAL Ion geometry = TETRAHEDRAL POLAR covalent bonds; NON POLAR species N H H H H + NH H H H + REDRAW!! ALL ANGLES 109.5° Ammonia , NH 3 Valence e = 5 + (3x1) = 8 RHED = 4 Electronic geometry = TETRAHEDRAL.
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This note was uploaded on 11/09/2010 for the course CH 301 taught by Professor Fakhreddine/lyon during the Fall '07 term at University of Texas.

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CH13 Notes Part 4 Example Worksheets Answers - Beryllium...

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