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Unformatted text preview: the designated protons at the compounds given below. You must show your calculations and provide a brief explanation for your answer (10 pts/each). 1.20 + 2.30 + 0.30 = 3.80 ppm 1.20 + 0.55 + 1.10 = 2.85 ppm (4) Calculate the difference in the absorbance frequency in Hz for two signals that appear at 1.0 and 2.5 ppm on an NMR spectrum obtained using 500 MHz field strength magnet (10 pts). (1.5 ppm)(500 Hz/ppm) = 750 Hz (5) Draw the splitting pattern for the protons of ethyl bromide (CH 3 CH 2 Br) (10 pts.) Cl Cl H H A B O R O R H H...
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This note was uploaded on 11/10/2010 for the course CHE Intermedia taught by Professor Dr.richard during the Spring '10 term at SUNY Buffalo.
- Spring '10