Problem set 1 - Question 1 of 12 8.57 10.0 Points Which of...

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Question 1 of 12 8.57/ 10.0 Points Which of the given compounds are aromatic? Select all that apply. Answer Key: A, C, F, H, I, M, P Feedback: To be aromatic a compound must be cyclic, planer, conjugated and have an odd number of pairs of pi electrons. Compounds A, C, F, H, I, M, and P are aromatic. Compound B has 6 electron pairs, compound D has an sp3 carbon, compound E has either sp3 oxygens or 4 electron pairs, compound G has no pi electrons, compound J is not cyclic, compound K has 2 electron pairs, compound L has 4 electron pairs or an sp3 N, compound N has 4 electron pairs, and compound O has 2 electron pairs so none of these are aromatic. Question 2 of 12 1.67/ 5.0 Points What is the name of given compound. Select all that are correct (IUPAC or common). Answer Key: D, H, I Feedback: The correct IUPAC name for the compound is 3- chlorobenzaldehyde. meta-Chlorobenzaldehyde or m-chlorobenzaldehyde are also commonly accepted for substituents in the 3 position (neither next to nor opposite the main substituent). Question 3 of 12 2.5/ 5.0 Points What is the name of given compound. Select all that are correct (IUPAC or common). Answer Key: B, C Feedback: This compound is sec-butoxybenzene (or 2-butylbenzene) using IUPAC nomenclature or sec-butyl phenyl ether using alkyl group nomenclature.
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