HW(0320) - . At that location We need to find the location...

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1. (a) N = (5.03 × 10 15 ) × 1.0 × 350 s –1 = 1.8 × 10 18 s –1 (b) N = (5.03 × 10 15 ) × 100 × 550 s –1 = 1.8 × 10 20 s –1 2. p = mv and Therefore, 3. 4.
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5. The maximum probability occurs at , corresponding to x = 1/2 L
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Unformatted text preview: . At that location We need to find the location at which . This corresponds to the angle at which. This is , corresponding to or 6. Therefore The normalized wave function is...
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HW(0320) - . At that location We need to find the location...

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