Lab_report_4 - 8.314 = 38693.356= 38 693 J/mol The...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Part 1:- 1) rate = ∆S / ∆t = k [S 2 O 3 2- ] m ln ∆S / ∆t = ln k [S 2 O 3 2- ] m ln ∆S – ln ∆t = ln k + ln [S 2 O 3 2- ] m ln ∆S – ln ∆t = ln k + m x ln [S 2 O 3 2- ] – ln ∆t = m x ln [S 2 O 3 2- ] + ln k – ln – ln ∆t = m x ln [S 2 O 3 2- ] + (ln k / ln ∆S) y = mx + b b y = -ln ∆t, x = ln [S 2 O 3 2- ] , b = (ln k / ln ∆S) 2) By using the regression feature in SigmaPlot, the order of the reaction is 1.0179. However, since the order needs to be an integer, this is rounded to 1. Therefore, the reaction is 1 st order with respect to [S 2 O 3 2- ]. y = 1.0179x + 1.2513 -5 -4.5 -4 -3.5 -3 -2.5 -2 -1.5 -1 -0.5 0 -3.5 -3 -2.5 -2 -1.5 -1 -0.5 0 ln t ln S2O3 Effect of Concentration on Reaction Rate
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Part 2:- 3) The slope of the line is 4654. 4) – ln ∆t = ln A – E a / R (1/T) slope = - E a / R E a = - slope x R = 4654 x
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 8.314 = 38693.356= 38 693 J/mol The activation energy for the reaction between two compounds is 38693 J/mol. 5) ln k = ln A E a / R (1/T) At k 1 , the temperature is 21 C (294 K). The reaction rate doubles at T 2. Therefore, ln [k 1 / k 2 ] = ln A E a / R (1/T 1 ) ln A + E a / R (1/T 2 ) ln [1 / 2] = E a / R [1/T 2 1/298] -0.6931 = 38693.356 / 8.314 [1/T 2 1/294] 3.252 x 10-3 = 1 / T 2 T 2 = 307.462 K = 34.46 C = 34 C To double the reaction rate, the reaction would have to be heated from 25 C to 34 C. y = 4654x - 11.236 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 0.00295 0.003 0.00305 0.0031 0.00315 0.0032 0.00325 0.0033 0.00335 0.0034 0.00345 ln t 1/T Effect of Temperature on Reaction Rule...
View Full Document

Page1 / 2

Lab_report_4 - 8.314 = 38693.356= 38 693 J/mol The...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online