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Unformatted text preview: sample from a normal population with 3.7, 0.73, 100 x n = = = . Solution. From the Ztable we know that 0.025 1.96 Z = , Therefore the 95% CI for is: 3.7 3.7 0.73 1.96 ,0.73 1.96 100 100 + Now we present the derivation of the general formula. 3 Let be any small positive value less than 1 (*usually less than 0.5), in the above figure, we have: / 2 /2 ( ) 1 P Z Z Z = /2 /2 /2 / 2 / 2 /2 ( ) 1 ( ) 1 ( ) 1 X P Z Z n P Z X Z n n P X Z X Z n n  =  =  + =  The 100(1)% confidence interval for (when 2 is known and the population is normal) is / 2 / 2 , X Z X Z n n + 4...
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This note was uploaded on 11/14/2010 for the course AMS 312 taught by Professor Zhu,w during the Spring '08 term at SUNY Stony Brook.
 Spring '08
 Zhu,W

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