APSC 150 Case 3- Lab 5 Problems

APSC 150 Case 3- Lab 5 Problems - b The content(wt of...

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APSC 150 - Case 3: Separation of Minerals by Froth Flotation. Laboratory 5 1) How many 30-m 3 flotation cells would be required in a flotation bank to process 10,000 tonnes of dry ore per day, at a solids content in the pulp of 30% (wt), and a flotation time of 22 minutes ? The SG of the ore is 3.0. 2) A mixture composed of 20 kg of Mineral A and 80 kg of Mineral B is floated in a bank of 6 cells with a residence time, τ , of 120 seconds in each cell. The flotation rate constants, k , are 0.8 min -1 and 0.01 min -1 for Mineral A and Mineral B, respectively. Based on this information calculate: a) The content (wt%) of Mineral A in the combined concentrate from the first three cells.
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Unformatted text preview: b) The content (wt%) of Mineral A in the concentrate from the third cell only. c) The recovery (%) of Mineral A in the concentrate from the fifth cell only. d) The content (wt%) of Mineral A in the final tailings exiting the entire bank. 3) The mass balance equation for a flotation separation can be written as: m F * M F = m C * M C + m T * M T where m F , m C, and m T are the masses of ore feed (F), concentrate (C), and tailings (T), respectively. M F , M C , M T are the metal (or mineral) contents (wt%) in ore feed, concentrate, and tailings. How would you define the recovery of metal (or mineral) in the concentrate from the above equation ?...
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This note was uploaded on 11/14/2010 for the course APSC 150 taught by Professor Muhan during the Spring '10 term at Wooster.

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