MEM427_HW_2_Solution

MEM427_HW_2_Solution - MEM427 HW Assignment#2 Solutions...

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Unformatted text preview: MEM427 HW Assignment #2 Solutions Fall 2010 1 / 2 Homework Assignment 2 A truss made from Douglas ‐ fir wood is subjected to an inclined force of P = 400 lb at joint as shown in the figure. Each member has a cross ‐ sectional area of 8.0 in 2 and a modulus of elasticity of E = 1.90 x 10 6 lb/in 2 . Determine the displacements at joint and the forces in all members by using the finite element method. Solution: The element stiffness matrix is given by 2 2 2 2 2 2 2 2 ) ( sin cos sin sin cos sin cos sin cos cos sin cos sin cos sin sin cos sin cos sin cos cos sin cos L AE e K Element 1 ‐ 2: 0.8 sin , 6 . cos in, 30 psi, 10 9 . 1 , in . 8 6 2 L E A 6 6 ) 2 1 ( 10 3243 . 2432 . 3243 . 2432 . 2432 . 1824 . 2432 . 1824 ....
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MEM427_HW_2_Solution - MEM427 HW Assignment#2 Solutions...

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