Version
– Exam 1 – Sutcliffe –
1
This
printout
should
have
30
questions.
Multiplechoice questions may continue on
the next column or page – find all choices
before answering.
001
10.0 points
Which of the following groups of atoms is
correctly arranged in order of decreasing first
ionization energy?
1.
Ge
>
As
>
Se
2.
Cl
>
Br
>
I
correct
3.
Rb
>
K
>
Na
4.
In
>
Ge
>
P
Explanation:
First ionization energy increases as one
moves from left to right on a given row and
increases from bottom to top as one moves up
a given family.
002
10.0 points
Choose the pair of names and formulae that
do not match.
1.
SCl
4
: sulfur tetrachloride
2.
N
2
O
3
: dinitrogen trioxide
3.
KNO
3
: potassium nitrate
4.
MgSO
4
: magnesium sulfate
5.
SnCl
4
: tin(V) chloride
correct
Explanation:
003
10.0 points
Note: you can find helpful conversions on the
back of the scantron we provide you.
A pipe drips at 155 mL/min.
Express this is units of gallons/day.
1.
2.34 gal/day
2.
0.223 gal/day
3.
15.7 gal/day
4.
223 gal/day
5.
58.9 gal/day
correct
6.
942 gal/day
7.
377 gal/day
Explanation:
? gal
day
=
155 mL
min
×
1 L
1000 mL
×
1 gal
3
.
785 L
×
60 min
1 hr
×
24 hr
1 day
=
58
.
9 gal
day
004
10.0 points
The following three statements refer to the
Bohr theory of the atom.
Z1) An electron can remain in a particular
orbit as long as it continually absorbs
radiation of a definite frequency.
Z2) The lowest energy orbits are those closest
to the nucleus.
Z3) An electron can jump from an inner orbit
to an outer orbit by emitting radiation of
a definite frequency.
Which response contains all the statements
that are consistent with the Bohr theory of
the atom and no others?
1.
Z2 and Z3 only
2.
Z3 only
3.
Z1 and Z2 only
4.
Z1, Z2 and Z3
5.
Z2 only
correct
Explanation:
005
10.0 points
In an atom the maximum number of electrons
having the quantum numbers
n
= 6 and
ℓ
= 3
is
1.
72.
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Version
– Exam 1 – Sutcliffe –
2
2.
14.
correct
3.
6.
4.
10.
5.
7.
Explanation:
14 electrons can have this set of quantum
numbers.
Where
ℓ
= 3, seven values of
m
ℓ
are possible, namely, 3, 2, 1, 0,

1,

2, and

3.
Each one of these
m
ℓ
values represents
a single orbital, so there are 7 orbitals. Since
each orbital can accomodate 2 electrons, 14
electrons can have this set of
n
and
ℓ
values.
006
10.0 points
Chromium and manganese both have five 3
d
electrons.
1.
False; chromium has four 3
d
electrons,
but manganese has five 3
d
electrons.
2.
True;
one
of
the
4
s
electrons
from
chromium prefers to move to a 3
d
orbital to
form a halffilled
d
shell.
correct
3.
False; chromium has five 3
d
electrons, but
manganese has six 3
d
electrons.
4.
True; one of the 3
d
electrons from man
ganese prefers to move up to a 4
s
orbital to
form a filled
s
shell.
5.
False; chromium has six 3
d
electrons and
manganese has seven 3
d
electrons.
Explanation:
Cr and Mg both have five 3
d
electrons. Cr
obtains additional stability by adding one of
the electrons bound for the 4
s
orbital to the
3
d
orbital instead.
The additional stability
comes from the fact that halffilled orbitals
(ex: five 3
d
electrons) are more energetically
stable.
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 Spring '07
 Fakhreddine/Lyon
 Chemistry, Atom, Electrons, Potassium nitrate

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