Ch 301 HW 2

# Ch 301 HW 2 - – Homework 2 – Sutcliffe –(52380 1 This...

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Unformatted text preview: – Homework 2 – Sutcliffe – (52380) 1 This print-out should have 20 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points Starting in the ground state n = 1 in a hydro- gen atom, an electron is excited to a higher energy level by absorption of 121.6 nm light. What is the final energy state of the electron? 1. n = 2 correct 2. n = 7 3. n = 5 4. n = 4 5. n = 6 6. n = 3 Explanation: 121.6 nm is a frequency of 2 . 47 × 10 15 s- 1 . That corresponds to a transition from n =1 to n =2 using the Rydberg formula. 002 10.0 points If a particle is confined to a one-dimensional box of length 300 pm, for Ψ 3 the particle is most likely to be found at 1. 50, 150, and 250 pm, respectively. cor- rect 2. 0 pm. 3. 300 pm. 4. 17.3 pm. 5. 100 and 200 pm, respectively. Explanation: 003 10.0 points A quantum mechanical particle in a box in its ground state is most likely to be found 1. in the middle of the box. correct 2. at both edges of the box. 3. at the very edge of the box. 4. is equally likely to be found at all positions except the very center of the box. 5. is equally likely to be found at all positions in the box. Explanation: The ground state is Ψ 1 which has maximum probability in the middle of the box. 004 10.0 points Set(s) of possible values of m ℓ are A)- 4;- 3;- 2;- 1; 0; +1; +2; +3; +4 B)- 3;- 2;- 1; 0; +1; +2; +3 C)- 2;- 1; 0; +1; +2 D)- 1; 0; +1 E) 0 Select the best choice for n = 3. 1. only D and E 2. only C 3. only B 4. only B, C, D, and E 5. only C, D, and E correct 6. only D 7. A, B, C, D, and E 8. only E 9. only A Explanation: For any value of n , the possible values of ℓ range from 0 up to ( n- 1). In turn, for any value of ℓ , the possible values of m ℓ range from =- ℓ , ..., 0, ..., + ℓ . Since n = 3, ℓ can be 0, 1, or 2. Therefore when ℓ = 2, C) m ℓ =- 2;- 1; 0; +1; +2 – Homework 2 – Sutcliffe – (52380) 2 when ℓ = 1, D) m ℓ =- 1; 0; +1 when ℓ = 0, E) m ℓ = 0 005 10.0 points The three quantum numbers for an electron in a hydrogen atom in a certain state are n = 4, ℓ = 2, m ℓ = 1. The electron is located in what type of orbital? 1. 4 s 2. 3 d 3. 4 d correct 4. 3 p 5. 4 p Explanation: The notation is n ℓ , where n = 1 , 2 , 3 , 4 , 5 , ... , ℓ = 0 , 1 , 2 , ..., ( n- 1) represented as a letter: ℓ 1 2 3 4 5 etc....
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## This note was uploaded on 11/15/2010 for the course CH 301 taught by Professor Fakhreddine/lyon during the Spring '07 term at University of Texas.

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Ch 301 HW 2 - – Homework 2 – Sutcliffe –(52380 1 This...

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