Population Ecology Practice Problems

Population Ecology Practice Problems - 0.15 under ideal...

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Population Ecology Practice Problems BSCI 110B Formulas: ! N/ ! t = rN N t = N 0 e rt Nt = ! t N 0 r = b-d ! N/ ! t = rN[(K-N)/K] e=2.718 1. What will be the size of a population with discrete generations in five generations if N=15 now? ! = 1.664 and there is no density dependence. 2. What would be the size of population with discrete generations in six generations if N = 900 now and ! = 0.86? 3. If the per capita birth rate in a population is 0.35/dya and the per capita death rate is 0.20/day, what is ! N/ ! t when N = 100? How large with the population be in 6 days, if there is no limitation on population growth and N = 100 at the start of the period? The species has overlapping generations. 4. What will ! N/ ! t be in a population of N = 100 whose intrinsic rate of increase (r) is
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Unformatted text preview: 0.15 under ideal conditions, but which has a carrying capacity K of 500 Calculate ! N/ ! t for this population when N = 450. The species has overlapping generations. 5. Consider the population mentioned in the question 4. It is a species of large mammal and t is measured in one year units. What will be the population size in one year if N = 50 now? Answers. 1. N ~ 191 2. N ~ 364 3. r = 0.15 ! N/ ! t = 15, N = 246 4. ! N/ ! t = 12, ! N/ ! t = 6.75 5. First you need to calculate ! N/ ! t for N = 50, and add that to 50 to get the new N in one year. So, ! N/ ! t = 6.75, therefore N = 50 + 6.75 = 56.75...
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This note was uploaded on 11/12/2010 for the course BSCI BSCI 110B taught by Professor Johnson during the Spring '09 term at Vanderbilt.

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