Background - Section A The capacitance can be calculated if...

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Section A The capacitance can be calculated if the geometry of the conductors and the dielectric properties of the insulator between the conductors are known. For example, the capacitance of a parallel- plate capacitor constructed of two parallel plates of area A separated by a distance d is approximately equal to the following: or where C is the capacitance in farads , F ϵ s is the static permittivity of the insulator used (or 0 for a vacuum) A is the area of each plate, measured in square metres r is the relative static permittivity (sometimes called the dielectric constant) of the material between the plates, (vacuum =1) d is the separation between the plates, measured in metres Coaxial Cable C = 2 p  ε 0 ε x   ln [ b/a ] A = Area of plates C = Capacitance (F) D = Distance between plates (m) a = Inner radius (m) b = Outer radius (m) q = Charge (Coulombs) x = Length (m) W = Energy (J) ε r  = Relative permittivity ε 0  = 8.85 x 10 -12  F/m D.F. = Dissipation Factor = 1/q
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Background - Section A The capacitance can be calculated if...

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