Section 12.4

Section 12.4 - x 2 + y 2 = 4 and x 2 + y 2 = 2 x 1.09587...

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12/9/08 7:45 PM Section 12.4 Page 1 of 2 http://www.webassign.net/v4cgiblmickle@ncsu/student.pl?p=20081210004511blmickle@ncsu15278239 Section 12.4 (Homework) MICKLES BRANDON L MA 242, section 008, Fall 2008 Instructor: April Alston Web Assign Current Score: 16 out of 16 Due: Friday, October 24, 2008 10:02 PM EDT Description Double Integrals in Polar Coordinates The due date for this assignment is past. Your work can be viewed below, but no changes can be made. 1. [SCalcCC2 12.4.12.] 3/3 points Evaluate the given integral by changing to polar coordinates. , where R is the region in the first quadrant enclosed by the circle x 2 + y 2 = 25 582.152 582 2. [SCalcCC2 12.4.14.] 3/3 points Evaluate the given integral by changing to polar coordinates. , where D is the region in the first quadrant that lies between the circles
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Unformatted text preview: x 2 + y 2 = 4 and x 2 + y 2 = 2 x 1.09587 1.1 3. [SCalcCC2 12.4.16.] 3/3 points Use polar coordinates to find the volume of the given solid. Inside the sphere x 2 + y 2 + z 2 = 16 and outside the cylinder x 2 + y 2 = 4 12/9/08 7:45 PM Section 12.4 Page 2 of 2 http://www.webassign.net/v4cgiblmickle@ncsu/student.pl?p=20081210004511blmickle@ncsu15278239 174 174 4. [SCalcCC2 12.4.18.] 3/3 points Use polar coordinates to find the volume of the given solid. Bounded by the paraboloid z = 10 - 3 x 2- 3 y 2 and the plane z = 4 18.8496 18.8 5. [SCalcCC2 12.4.26.] 4/4 points Evaluate the iterated integral by converting to polar coordinates. (pi/5)*a^5 (1/5)*pi*a^5...
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This note was uploaded on 11/15/2010 for the course MA 242 taught by Professor Bliss during the Spring '08 term at N.C. State.

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Section 12.4 - x 2 + y 2 = 4 and x 2 + y 2 = 2 x 1.09587...

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