fisica lab 3.docx - M5= 109.51 M6= 114.81 Fe=200.15 204\u00b0 =0,10951 \u00d7 9,8=1,07 N KG 0,001 1 kg 0,001 B= 114,81 1 kg)=0,11481 \u00d7 9,8=1,13 N\/KG A= 109,51g

# fisica lab 3.docx - M5= 109.51 M6= 114.81 Fe=200.15 204°...

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M 5= 109.51 Fe=200.15, 204° M 6= 114.81 A= 109,51g ( 0,001 1 kg ) = 0,10951 × 9,8 = 1,07 N / KG B= 114,81 ( 0,001 1 kg ) = 0,11481 × 9,8 = 1,13 N / KG F e = 200,15 ( 0,001 1 kg ) = 0,20015 × 9,8 = 1,10 N / KG Componentes A.IF Ax I=1,07N cos ( 0 )= 1,07 N IF Ay I=1,07N sen ( 0 )= 1,07 N B.IF Ax I=1,13N cos ( 204 ° )= 1,03 N C.IFAyI=1,13N sen(204°)=0,46N Fuerza resultante F x = 1,07N-1,03N

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