a1soln - CONCORDIA UNIVERSITY DEPARTMENT OF COMPUTER...

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Unformatted text preview: CONCORDIA UNIVERSITY DEPARTMENT OF COMPUTER SCIENCE & SOFTWARE ENGINEERING COMP 232/2 Mathematics for Computer Science FALL 2010 Assignment 1 Solutions 1. In each of the three cases A is a knight and B is a knight , A is a knight and B is a knave , A is a knave and B is a knave , A would have answered yes, and in the case A is a knave and B is a knight A would have answered no. Since As answer determines the status of A and B uniquely, As answer must have beeen no, and it follows that A is a knave and B is a knight. 2. a) Tautology b) Contingency c) Contingency 3. a) ( p F ) p ( p F ) p ( p F ) p p p p p T b) ( p q ) ( p r ) ( q r ) ( ( p q ) ( p r ) ) ( q r ) ( p q ) ( p r ) ( q r ) ( p q ) ( p r ) ( q r ) ( p q ) ( p r ) ( q r ) ( ( p...
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This note was uploaded on 11/15/2010 for the course ENCS COMP 232 taught by Professor Ford during the Fall '10 term at Concordia CA.

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a1soln - CONCORDIA UNIVERSITY DEPARTMENT OF COMPUTER...

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