10SimHw8Solution

10SimHw8Solution - n M and the size of the inspection queue...

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IEOR E4404.001 Assignment #8 Solutions SIMULATION March 24, 2010 Prof. Mariana Olvera-Cravioto Assignment #8 Solutions 1. We are trying to reach an absolute error of 0.5 with 99 S 2 (20) = 282 . 24 z 1 - 0 . 99 / 2 = 2 . 5758 m p z 1 - 0 . 99 / 2 r S 2 ( n ) β P 2 7490 2. Just substitute σ 2 by the sample variance. = var ( 1 n n s i =1 X i ) = 1 n 2 2 = σ 2 n S 2 (16) n If we set this to be smaller than 0 . 1 2 , we get n 907 3. We should keep four timers and two variables. The timers should be Time to next arrival t A Time to completion of machining t M Time to completion of inspection t I Time to completion of repair of machine t R The two variables are the size of the machine center queue
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Unformatted text preview: n M and the size of the inspection queue n I . Loop the four following cases (until some terminating condition i.e. t < T ) • t A = min t A , t M , t I , t C • t M = min t A , t M , t I , t C – t = t M – if n 1 = 1 set t M = ∞ – else set t M = t + Uniform [0 . 65 , . 70] – n 1--– n 2 + + • t I = min t A , t M , t I , t C l p would be a good warm-up period. This is because when X ( n ) has stabilized, that means the underlying Y i process is closer to steady state. 4. (a)...
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10SimHw8Solution - n M and the size of the inspection queue...

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