Unformatted text preview: k 1 t k c k,n ( q ) , so c k,n ( q ) = t k F n ( t, q ) . The problem is to determine this coecient. By considering an expression for F n ( tq, q ) that involves F n ( t, q ) , prove that c k,n ( q ) = k Y i =1 ( 1q n + i )( 1q i )1 . F Bonus : (15 points) Find a natural bijection that accounts of the result given in Question A. 1...
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 Spring '05
 R.Metzger
 Power Series, Taylor Series, FN, power series expansion, tk Fn

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