hw6_f10 - μ = τ log n n Q(1 This was derived by...

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Physics 112, Fall 2010: Holzapfel Problem Set 6 (6 problems). Due Wednesday, October 13, 5PM Problem 1 : Centrifuge Kittel 5.1 Problem 2 : Active Transport Kittel 5.4 Problem 3 : Carbon monoxide poisoning Kittel 5.8 Problem 4 : Concentration Fluctuations Kittel 5.10 Problem 5 : Ascent of sap in trees Kittel 5.12 Problem 6 : Another derivation of the chemical potential of an ideal gas We found in class and it is shown in the textbook that the chemical potential of an ideal gas is
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Unformatted text preview: μ = τ log n n Q . (1) This was derived by differentiating the free energy, according to the equation μ = ± ∂ F ∂ N ² τ , V . (2) But we also found that μ =-τ ± ∂σ ∂ N ² U , V . (3) Starting from the entropy of an ideal gas of indistinguishable particles (The Sackur-Tetrode equation) show that one reproduces equation (1) for the chemical potential of an ideal gas. 1...
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This note was uploaded on 11/18/2010 for the course PHYSICS 112 taught by Professor Steveng.louie during the Fall '06 term at Berkeley.

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