lc10sol - Jim Lisy « CHEM 204 Spring 2010 l Homework 10...

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Unformatted text preview: Jim Lisy « CHEM 204 Spring 2010 l Homework 10 Due date: Fri Apr 9 23:00:00 2010 ‘i Initial rate data are listed in the table for the reaction: NH4+ (aq) + N02“ (aq) ~~>N2 + H20 (1) ExpeflnuflfiH4+h " psoZt Infikfl rate ; (M/S) 1 2 3 iii? 4 m 0.12 First determine the rate law and rate constant. Under the same initial conditions as in Experiment 4, calculate [NHj‘] at 288 seconds after the start of the rew action. in this experiment, both reactants are present at the same initial concentration. The units should be M, and should be calculated to three sigr’rificant figures. E1..imsm_:::l You are correct. Your receipt is 1504675 fill“? ‘ a «a 0.0589 01 a” [o . 0580253932716668 , ; 0 o . 0648088139987038] g; g ca Unit: M Jim liisy ~ CHEM 204 Spring 2010 2 Egr'ic'uiorjlt 10 Kinetic data are normally presented as graphs. The fol— lowing questions test your knowledge about labeling and interpreting graphs correctly. [13] is used to represent the concentration of a reactant B in a reaction. A represents the Arrhenius factor and k represents a rate constant. Decide if each of the following statements is True or False. Choices: True, False. ’ é p, 3 A. Consider graph D: if y 2 1/ [B] and x 2 time, the 5:22; i ‘ X l i slope is equal to «k. . . .,1 r . -fi , if B. Consrder graph C: if y 2 in k and X 2 1/1, the an L4,, 6’ t intercept is equal to A. C. Consider graph C: if y 2 lnlB] and X 2 time, the graph could represent a second order reaction. D. Consider graph C: if y 2 [B] and X 2 time, the graph could represent a second order reaction. E. Consider graph B: if y 2 [B] and x 2 time, the graph h ’ I could represent a zero order reaction. ‘ ,1 ,V . F. Consider graph A: if y 2 and X 2 time, the graph “ a M l 1 could represent a zero order reaction. G. Consider graph D: if y 2 lnlB] and X 2 time, the 4, . \ e ; , c < 5 graph could represent a first order reaction. You are correct. Your receipt is 150—7668 I V Ans r ‘ .. , l f W}? t «2 False r 15,: . _ 00 a 6 False ta False 9 False cs False 4» False Jim Lisy — CHEM 204. Spring 2010 3 Homework 10 m i . . . ; Dec1de which of the followmg statements are True and A . ’ which are False. Choices: True7 False. A. The half~lite for a reaction aA —>products7 that is first order in A increases with [A]0. B. Actual reaction rates are lower than the collision fre— quency for ideal gases. C. The concentration of a catalyst never appears in the rate law of a reaction. D. The halfulife of a second order reaction increases as I the reaction proceeds. E. Endotherniie reactions always have higher activation energies for the forward reaction than for the reverse reaction. You are correct; Your receipt is 150—1762 Answer @ Pal S e for Part: . a True 0 a Fal s e a True 9 True The rate constant for a first order reaction is 006091. when the temperature is increased from 298K to 380 K , the rate constant increases to 0.18s'1. Calculate the acti~ vation energy for this reaction. Use kJ/mol for the units. The activation energy in kJ/mol equals (include the units in your answer): E::::: Wm You are correct. Your receipt is 15047799 .Answer a 12.6136414292538 for Part: [11.9829593577911 13.2443235007165] a Unit: kJ/mol A biologist observes that a cricket chirps 45 times a minute at 22°C and 75 times a minute at 35°C. Assuming that the body processes that cause a cricket to chirp depend on the kinetics of the cricket’s biochemical reactions, answer the following questions. Choices: True, False. A. The cricket’s chirping should increase linearly with i v ’ ’ temperature. 2, r B. The cricket would be expected to chirp 40 times per minute at 190 C. “ ‘M C. The cricket would be expectedgto chirp 86 times per minute at 40° C rm, ‘sgx “5.2/2” Jim Lisy ~ CHEM 204 Spring 2010 4 gfyflework 10 Calculate the value of the activation energy for the cricket’s chirping (in J or kJ Youjrre correct Your receipt is 150m2§§2 ____________ __ Answer f . P! .t. a False 1021 (M ' a True 0 False Answer (9 29680 for Part: 14 [29.384985658532831 29978 . 6217627939] Unit: J a The reaction 2Noz—>2No+o2 obeys the rate law: i ii i: mm2L4xm4moghmm0K. was What would be the rate constant at 165 K if the activation energy is 80. kJ/mol? This is a second order reaction giving k the units of 3/1484 This will not change with the change in temperature. Do not include units in your answer. Exponential numbers need to be entered like this: 2 El means 2 X 10‘1. The rate constant, k, at 165 K equals: 1.: mmmmmmmmmm _ _, You are correct“ Your receipt is 1504678 f???” @ .50e-~19 01 a” [1 (42875495691777919 0 1.57915021554069e~19] According to the kinetic theory, collisions between molecules in a gas 7777777. A. cause a loss of total kinetic energy are perfectly elastic are inelastic: Dow . never OCCUI‘ You are correct. Answer a f a1 S e for Part: a true 0 s f a1 5 e e f a1 3 e Cm Jim Lisy »- CHEM 204 Spring 2010 Homework 10 Which description best fits how enzymes typically catalyze reactions? A. Covalent bonds between the enzyme an the sul} {é 9;; {l strate lower the AG: of the reaction. cfo~\ B. Weak interactions between the enzyme anc substrate lower the Km of the reaction. C. Weak interactions between the enzyme anc substrate lower the AG of the reaction. it: ' t’ e D. Covalent bonds between the enzyme anc subl I; Si (. strate lower the AG of the reaction. w fife“; " I l t" "\ l ' E. Covalent bonds between the enzyme an the sub i E g. strate lower the Km of the reaction. ,5 F. Weak interactions between the enzyme an substrate i - v:,"”"‘\\'>~‘f , lower the AG of the reaction t e «.g ' You are correct. Your receipt is 150-8035 Answer ..... __... for Part: 0 a false 0: false 9 false a false 6 false 6 true .L E Reactams ,1 A “m. .4 Products Match the following: Choices: A, B, C, D, E. I A. High Energy of Activation. B. Rate Determining Transition State C. Non—«rate determining Transition State D. Intermediate You are correct. Your receipt is 1504957 Answer for O Jim. Lisy w CHEM 204 Spring 201.0 6 Homework 10 Reaction coordinate W V r W V a Match the following: Choices: A, B, (3,1), E, F, G, H, I, J, K, L. The transition state which limits the overall reaction rate. P> Activation energy (E!) for the overall process. Intermediate ” Dow “fly Energy of reaction (AE) . G Reactants You are correct, Your receipt is 150—1625 Answer a J for Part: g F O 6 H :3 A Jim Lisy ~ CHEM 204 Spring 2010 '7 Homework .10 Label the fol owing activation diagram. energy F i” e e E n e i” 9 . y Progress of Reaction MMWWWWWW A B C D E r“ :— The energy required for the products to reach the transition state in the reverse direction. “mm The overall free energy change of the reaction. """""" w Transition state Pym The activation energy required for an enzyme catalyzed reaction to progress in the forward direction. m" The activation energy required for an uncatalyzed reaction to progress in the forward direction, “an” The activation energy for an enzyme~catalyzed re- action. in the reverse direction. Ypu are cor_reet.),.Your receipt is 1507866 M Answer 5- ‘ " a for Part: F 0 M E f a D / i° A ‘i‘c‘k‘ficfl/ Printed from LON—CAPA9MSU Licensed under GNU General Public License ...
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This note was uploaded on 11/19/2010 for the course CHEM 204 taught by Professor Gruebele during the Spring '08 term at University of Illinois, Urbana Champaign.

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lc10sol - Jim Lisy « CHEM 204 Spring 2010 l Homework 10...

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