11 - Chem 204 Lecture11 With strong acids and bases, we...

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Chem 204 Lecture 11 With strong acids and bases, we really only need to worry about [H 3 O + ] and [OH - ]. However, with weak acids (or bases), titration will produce the conjugate base (or acid). This means that we will make a buffer-like solution when we titrate. Why? If we start with a weak acid, neutralizing with a strong base will result in [HA] and [A - ]. At the ½ equivalence point, [HA]=[A - ], pH=pK a . At equivalence point, the major species is [A - ].
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Lecture 11 –Page 2 Consider the neutralization of a weak base by titration with a solution of acid, in more detail. B(aq)+H 3 O + (aq) HB + (aq)+H 2 O As noted on the last slide, as we neutralize the base, we will produce the conjugate acid. It’s good practice to know what’s in solution. Always need to ID major species! I will underline! http://www.chembio.uoguelph.ca/educmat/chm19104/chemtoons/titration_figure5.jpg Let’s walk through this to make sure we know what’s
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Lecture 11 –Page 3 Start with 20 mL of 0.200 M NH 3 (K b =1.8x10 -5 ) Titrate with 0, 4.0, 10.0, 11.0 mL of 0.400 M HNO 3 . Strong acid!
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11 - Chem 204 Lecture11 With strong acids and bases, we...

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