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Unformatted text preview: The due date for this assignment is past. Your work can be viewed below, but no changes can be made. View Key A spring whose stiffness is 1110 N/m has a relaxed length of 0.57 m. If the length of the spring changes from 0.32 m to 0.88 m, what is the change in the potential energy of the spring? Δ U = 18.648 J Page 1 of 2 Ch7 HW1 f10 11/21/2010 http:[email protected][email protected] .. (a) At r = r 1 , what are the approximate values of the kinetic energy K , the potential energy U , and the quantity K + U ? K = 1.1 eV U = -1.3 eV K + U = -.2 eV (b) What minimum (positive) amount of energy must be supplied to cause these two atoms to separate? .2 eV Page 2 of 2 Ch7 HW1 f10 11/21/2010 http:[email protected][email protected] .....
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This note was uploaded on 11/21/2010 for the course PHY 56665 taught by Professor Chelikowsky during the Fall '10 term at University of Texas at Austin.
- Fall '10