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Unformatted text preview: mcconnell (kam2342) homework25 Turner (60230) 1 This printout should have 10 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 2) 10.0 points An electric motor has 115 turns of wire wrapped on a rectangular coil, of dimensions 2 . 3 cm by 4 . 33 cm. Assume that the mo tor uses 11 . 6 A of current and that a uniform . 618 T magnetic field exists within the mo tor. What is the maximum torque delivered by the motor? Correct answer: 0 . 821032 N m. Explanation: Let : w = 2 . 3 cm , = 4 . 33 cm , I = 11 . 6 A , and B = 0 . 618 T . Force : vector F = I vector vector B Torque : vector = vectorr vector F Power : P = . Magnetic force exerted on the 4 . 33 cm side is, F = N I B = (115 turns) (11 . 6 A) (0 . 0433 m) (0 . 618 T) = 35 . 697 N . So, the maximum torque on the loop due to the magnetic field is max = F w = (35 . 697 N) (0 . 023 m) = . 821032 N m . 002 (part 2 of 2) 10.0 points If the motor rotates at 4170 rev / min, what is the peak power produced by the motor? Correct answer: 358 . 529 W. Explanation: P = = (0 . 821032 N m) (436 . 681 s 1 ) = 358 . 529 W . 003 10.0 points A long solenoid has a coil made of fine wire inside it and coaxial with it. I Outside solenoid has n turns per meter Inside coil has N turns r R Given a varying current I in the outer solenoid, what is the emf induced in the inner loop? 1. E = R N dI dt 2. E = R 2 nN dI dt correct 3. E = R n dI dt 4. E = r nN dI dt 5. E = r N dI dt 6. E = r 2 nN dI dt 7. E = r n dI dt 8. E = R nN dI dt 9. E = R 2 n dI dt 10. E = r 2 n dI dt Explanation: The magnetic field of a solenoid is B = nI . The magnetic flux is B = B A = ( nI ) ( R 2 ) , mcconnell (kam2342) homework25 Turner (60230) 2 so the emf is E = d B dt = R 2 nN dI dt . We are interested in the emf in the inner coil, so we use the smaller area of the inner coil rather than the larger solenoid area. keywords: 004 (part 1 of 2) 10.0 points Two infinitely long solenoids (seen in cross section in the figure below) thread a circuit. Given: a = 0 . 6 m , r 1 = 0 . 2 m , r 2 = 0 . 1 m , B t = 90 T / s , R l = 8 . 7 , R m = 5 . 6 , and R r = 2 . 5 , as in the figure below. The magnitude of B inside each solenoid is the same and is 300 T at time t = 0. B in B out I l I m I r r 2 R m R l R r r 1 a a a What is the magnitude of the current, I m , in middle resistor, R m ? Correct answer: 0 . 625938 A. Explanation: Basic Concept: Faradays Law: E = d B dt Ohms Law: I = V R Junction Rule: n summationdisplay i =1 I i = 0 Solution: Note: The sidelength, a , of the circuit loop is not necessary for this problem....
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 Spring '10
 Turner

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