This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: mcconnell (kam2342) homework26 Turner (60230) 1 This printout should have 12 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 3) 10.0 points A metal strip 2 . 2 cm wide and 0 . 13 cm thick carries a current of 16 A in a uniform magnetic field of 1 . 8 T. The Hall voltage is measured to be 4 . 33 V. The charge on an electron is 1 . 6 10 19 C. vector B 2 . 2 cm . 13 cm I a b Calculate the drift velocity of the electrons in the strip. Correct answer: 0 . 109343 mm / s. Explanation: Let : V H = 4 . 33 V = 4 . 33 10 6 V , B = 1 . 8 T , and w = 2 . 2 cm = 0 . 022 m . The Hall voltage as a function of the drift velocity of the electrons in the strip is V H = v d B w , so v d = V H B w = 4 . 33 10 6 V (1 . 8 T) (0 . 022 m) 10 3 mm 1 m = . 109343 mm / s . 002 (part 2 of 3) 10.0 points The charge on the electron is 1 . 6 10 19 C. Find the number density of the charge car riers in the strip. Correct answer: 3 . 19773 10 28 m 3 . Explanation: Let : I = 16 A , t = 0 . 13 cm = 0 . 0013 m , and q = 1 . 6 10 19 C . The current is I = n A q v d n = I A q v d = I w t q v d = 16 A (0 . 022 m) (0 . 0013 m) 1 (1 . 6 10 19 C) (0 . 000109343 m / s) = 3 . 19773 10 28 m 3 ....
View
Full
Document
This note was uploaded on 11/22/2010 for the course PHYS 303 taught by Professor Turner during the Spring '10 term at University of Texas at Austin.
 Spring '10
 Turner

Click to edit the document details