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oldhw10_pdf - mcconnell(kam2342 – oldhomework 10 –...

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mcconnell (kam2342) – oldhomework 10 – Turner – (60230) 1 This print-out should have 13 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points A small electrically charged object is sus- pended by a thread between the vertical plates of a parallel-plate capacitor. The acceleration of gravity is 9 . 8 m / s 2 . A B vector E + - E 152 mg 15 nC θ θ =14 5 . 6 cm What is the potential difference between the plates? Correct answer: 1 . 38656 kV. Explanation: Let : m = 152 mg = 0 . 000152 kg , g = 9 . 8 m / s 2 , d = 5 . 6 cm = 0 . 056 m , θ = 14 , and q = 15 nC = 1 . 5 × 10 8 C . A B vector E + - E m q θ d The forces acting on the particle are the tension T on the thread, the weight m g and the electric force q E = q V d . Since the par- ticle is in equilibrium, the resultant force is equal to zero; i.e. , T sin θ = q V d T cos θ = m g Dividing, tan θ = q V m g d V = m g d tan θ q = (0 . 000152 kg) (9 . 8 m / s 2 ) (0 . 056 m) 1 . 5 × 10 8 C × tan 14 = 1 . 38656 kV . 002 (part 1 of 2) 10.0 points A 7 . 96 μ F capacitor is first charged by being connected across a 40 V battery. It is then disconnected from the battery and connected across an uncharged 6 . 98 μ F capacitor. Find the charge on the 7 . 96 μ F capacitor. Correct answer: 169 . 643 μ C. Explanation: Let : C 1 = 7 . 96 μ F , C 2 = 6 . 98 μ F and V = 40 V .
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mcconnell (kam2342) – oldhomework 10 – Turner – (60230) 2 The initial charge of each capacitor is Q 1 = C 1 V , and Q 2 = 0 . After the capacitors are connected in paral- lel, the potential difference across each is the same, so Δ V = Q 1 C 1 = Q 2 C 2 Q 2 = Q 1 C 2 C
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