Assignment_5_Solution - kVAR. 3 such single phase...

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Assignment #5 – Chapter 5 Fall 2010- EE 362Q /EE 394.9 Power Quality Prof. S. Santoso (instructor) Example 5.4 Refer Textbook. Problem 5.1 a) F C C X Q kV X MVAR kVAR Q kv kV C LNrated C rated unit LNrated μ ω φ 66 . 7 1 112 . 346 2 . 0 32 . 8 2 . 0 200 32 . 8 2 1 2 , 1 = = Ω = = = = = = b) F C C X Q kV X MVAR kVAR Q kV kV C LNrated C actual unit LNactual 66 . 7 1 112 . 346 2 . 0 32 . 8 1834 . 0 408 . 183 32 . 8 967 . 7 200 967 . 7 3 8 . 13 2 1 2 2 , 1 = = Ω = = = = = × = = = c) F C C X Q kV X MVAR Q C LNrated C actual 66 . 7 1 112 . 346 2 . 0 32 . 8 1 . 1 3 2 1834 . 0 2 1 2 3 = = Ω = = = = × × = d) pu MVA Q V sc actual 0183 . 0 60 1 . 1 3 , 3 = = = Δ 1
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Problem 5.5 a) kVAR a a Q Q Q Q Q kW P P new old new old 875 . 580 )) 95 . 0 cos( ) 7 . 0 cos( tan( 840 840 7 . 0 1200 3 = × = Δ = = Δ = × = = φ b) pu MVA Q V MVA X MVA MVA sc T T sc 01742 . 0 33 . 33 580875 . 0 33 . 33 06 . 0 2 3 3 3 = = = Δ = = = c) kVAR Q 458 . 193 3 875 . 580 1 = = A parallel combination of 100, 60 and 35 kVAR single phase banks add up to 195
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Unformatted text preview: kVAR. 3 such single phase combinations are connected in delta. pu MVA Q V sc actual actual 01773 . 33 . 33 3 195 . 3 , 3 = = = Or A parallel combination of 100 and 100 kVAR single phase banks add up to 200 kVAR. 3 such single phase combinations are connected in delta. pu MVA Q V sc actual actual 018 . 33 . 33 3 2 . 3 , 3 = = = 2...
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Assignment_5_Solution - kVAR. 3 such single phase...

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