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Unformatted text preview: yang (ey942) oldhomework 11 turner (56705) 1 This printout should have 17 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 2) 10.0 points A parallelplate capacitor has a charge of 6 . 1 C when charged by a potential differ ence of 2 . 69 V . a) Find its capacitance. Correct answer: 2 . 26766 10 6 F. Explanation: Let : Q = 6 . 1 C and V 1 = 2 . 69 V . The capacitance is given by C = Q V = 6 . 1 10 6 C 2 . 69 V = 2 . 26766 10 6 F . 002 (part 2 of 2) 10.0 points b) How much electrical potential energy is stored when this capacitor is connected to a 1 . 55 V battery? Correct answer: 2 . 72402 10 6 J. Explanation: Let : V 2 = 1 . 55 V U electric = 1 2 C ( V ) 2 = 1 2 (2 . 26766 10 6 F) (1 . 55 V) 2 = 2 . 72402 10 6 J 003 (part 1 of 7) 10.0 points A capacitor network is shown in the following figure. 12 . 3 V 4 . 09 F 4 . 6 F 11 . 4 F a b What is effective capacitance C ab of the entire capacitor network? Correct answer: 13 . 565 F. Explanation: Let : C 1 = 4 . 09 F , C 2 = 4 . 6 F , C 3 = 11 . 4 F , and E B = 12 . 3 V . E B C 1 C 2 C 3 a b C 1 and C 2 are in series with each other, and they are together are parallel with C 3 . So C ab = C 1 C 2 C 1 + C 2 + C 3 = (4 . 09 F) (4 . 6 F) 4 . 09 F + 4 . 6 F + 11 . 4 F = 13 . 565 F . 004 (part 2 of 7) 10.0 points What is the voltage across the 4 . 6 F upper righthand capacitor? Correct answer: 5 . 78907 V. Explanation: Since C 1 and C 2 are in series they carry the same charge C 1 V 1 = C 2 V 2 , yang (ey942) oldhomework 11 turner (56705) 2 and their voltages add up to V , voltage of the battery V 1 + V 2 = V C 2 V 2 C 1 + V 2 = V C 2 V 2 + C 1 V 2 = V C 1 V 2 = V C 1 C 1 + C 2 = (12 . 3 V)(4 . 09 F) 4 . 09 F + 4 . 6 F = 5 . 78907 V . 005 (part 3 of 7) 10.0 points If a dielectric of constant 4 . 86 is inserted in the 4 . 6 F top righthand capacitor (when the battery is connected), what is the electric potential across the 4 . 09 F top lefthand capacitor? Correct answer: 10 . 3977 V. Explanation: Let : = 4 . 86 . When the dielectric is inserted, the capaci tance formerly C 2 becomes C 2 = C 2 , and the new voltage across C 1 is V 1 = V C 2 C 1 + C 2 = V C 2 C 1 + C 2 = (4 . 86)(12 . 3 V)(4 . 6 F) 4 . 09 F + (4 . 86)(4 . 6 F) = 10 . 3977 V . 006 (part 4 of 7) 10.0 points If the battery is disconnected and then the dielectric is removed, what is the charge on 4 . 09 F top lefthand capacitor? Correct answer: 29 . 1669 C. Explanation: Immediately before the battery was discon nected the charges on the capacitors had been Q 3 = C 3 V = (11 . 4 F)(12 . 3 V) = 140 . 22 C Q 1 = Q 2 = C 12 V = (3 . 45746 F)(12 . 3 V) = 42 . 5268 C ....
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 Spring '10
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