This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Chem 1P Lecture 12: Mole and molar mass Midterm results mean: 64.3 std. dev.: 18.8 Midterm results mean: 64.3 std. dev.: 18.8 Not bad! Midterm Midterm I is 15% of your total grade Grades will not be curved. Only your cumulative grade will be curved Your exam will be available on your EEE page Do not contest your score before the exam has been returned to you Genuine grading errors will be considered till Friday 11/5 Numerical problems One can of Coke fills a glass of 33 cL and weighs 350 g. What is the mass of the total amount of Coke needed to fill a small swimming pool that is 10.0 ft wide, 15.0 ft long and 2.6 ft deep? What do we need to calculate? mass = V x d Key here is a correct conversion from ft 3 to L 12 in 1 ft 2.54 cm 1 in x ) ( 1 ft = 1 ft x = 30 .48 cm V = 10.0 ft x (30 .48 cm/ft) x 15.0 ft x (30 .48 cm/ft) ft x 2.6 ft x (30 .48 cm/ft) = 10.0 x 15.0 x 2.6 x (30.48) 3 cm 3 = 1.1 x 10 7 cm 3 = 1.1 x 10 4 L Mass = 1.1 x 10 4 L x 350 g/0.33 L = 1.2 x 10 7 g = 1.2 x 10 1 Mg Naming compounds MnSO 3 manganese sulfite wrong manganese(II) sulfite right H 2 SO 4 (aq) dihydrogen sulfate sulfuric acid...
View
Full
Document
This note was uploaded on 11/23/2010 for the course CHEM Chem 1P taught by Professor Ericpotma during the Winter '10 term at UC Irvine.
 Winter '10
 EricPotma
 Chemistry, Mole

Click to edit the document details