Lecture16 - Chem 1P Lecture 16: Fun Difficult? Chang...

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Fun Chem 1P Lecture 16:
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Difficult?
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Puzzles Chang Section 3.7 - 3.8
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Balancing equations Ga + O 2 ˠ Ga 2 O 3 4 2 3 (Examples from WileyPlus) Chang Section 3.7 - 3.9 WileyPlus: Balancing chemical equations Enter the formula of the missing substance ( Y ) in the balanced equation below. Do not give the coefficient: 2Y + Br 2 ˠ I 2 + 2NaBr NaI Sr + P 4 ˠ Sr 3 P 2 6 2 Balance the following equations: 2H 2 S + 3Y ˠ 2SO 2 + 2H 2 O O 2
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Limiting reagents Chang Section 3.7 - 3.9 Consider the following reaction: 2 H 2 (g) + O 2 (g) 2 H 2 O (g) Assuming complete reaction, which of the diagrams shown represents the amounts of reactants and products left after the reaction?
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Limiting reagents Chang Section 3.7 - 3.9 A sample of compound of Cl and O reacts with an excess of H 2 to give 0.233 g of HCl and 0.403 g of H 2 O. Determine the empirical formula of the compound. 1. Write down the (unbalanced) chemical equation. Cl x O y + H 2 (g) HCl + H 2 O 2. Determine the mole ratio between reactants and products Each mole of Cl x O y produces: x mol of HCl y mol of H 2 O Finding the number of moles of HCl and H 2 O thus provides the desired ratio of the x and y coefficients!
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Limiting reagents Chang Section 3.7 - 3.9 A sample of compound of Cl and O reacts with an excess of H 2 to give 0.233 g of HCl and 0.403 g of H 2 O. Determine the empirical formula of the compound. 3. Find the number of moles of the products 0.233 g 1 mol HCl 36.46 g 1 mol H 2 O 18.02 g = 6.39 x 10 -3 mol HCl 0.403 g = 2.24 x 10 -2 mol H 2 O = 6.39 x 10 -3 mol of Cl = 2.24 x 10 -2 mol of O 4. Find the empirical ratio between Cl and O 6.39 x 10 -3 mol Cl 2.24 x 10 -2 mol O = 3.50 not close to an integer number!
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Lecture16 - Chem 1P Lecture 16: Fun Difficult? Chang...

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