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1
STA2023 – LAB 2
p
and
p
1
 p
2
)
A OneProportion Study
In a poll of 800 randomly selected adults, 8.5% said they are in favor of the cloning of human beings.
1.
How many of these 800 adults feel that cloning should be allowed?
Let this represent the number of
successes in your sample data.
Recall:
# of successes = n
*
p
2.
Assume that all of the necessary assumptions/conditions (page 493  plausible independence,
randomization, 10% condition, success/failure condition) have been met for approximating the
distribution of sample proportions (
^
p
values) with a normal distribution.
Use Minitab to find a 95% confidence interval for the proportion of all adults who feel that cloning
should be allowed.
Click on
STAT
,
Basic Statistics
, then
1Proportion
.
Since you have summary results (not the
individual data), click on the
Summarized Data
button.
Enter the number of successes (# of events
= 68) and number of trials (n = 800) into the appropriate fields.
Click the
Options
button to choose
the appropriate confidence level (95%).
Choose NOT EQUAL for the Alternative and click the
check box for Use Test and Interval Based on a Normal Distribution.
Click
OK
twice.
The
confidence interval results should now be in the session window.
Did you get
(0.065675, 0.104325)
?
Interpret the meaning of your confidence interval in the context of the given scenario.
3.
A newspaper reporter has seen this Gallup poll information and writes an article with the following
headline:
“More Than 7.5% of Adults Favor Cloning”.
Write an appropriate null and alternative
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 Spring '08
 Ripol
 Statistics

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