Workshop 5 Key-1

Workshop 5 Key-1 - Workshop #5 Chem 1A Fall 2010 1. The...

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Workshop #5 Chem 1A Fall 2010 1. The following orbital diagram corresponds to an atom in the -2 oxidation state. Identify the atom and give the electron configuration (in [Ar]5s x 4d y 5p z format) of the +2 oxidation state of that atom. 5s 4d 5p [Kr] An atom in the 2- oxidation state indicates that 2 electrons were added to a neutral atom. Removing two electrons gives the proper electron configuration for the starting atom, [Kr]5s 1 4d 10 . Using the periodic table, the atom with this electron configuration is Ag. To generate an atom in the 2+ oxidation state, 2 electrons need to be removed from the ground state. The resulting electron configuration is [Kr]5s 0 4d 9 . 2. The following data are for imaginary elements Ix, Jy, and Kz. Element IE 1 (kJ/mol) e - A(kJ/mol) Ix 352 -56 Jy 1762 -291 Kz 1597 -164 a. From which atom is it easiest to remove an electron? Ionization energy (IE) is the measure of energy required to remove an electron to generate a cation. The smaller the value of IE, the easier it is to
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This note was uploaded on 11/27/2010 for the course CHEM Chem 1A taught by Professor Benhafensteiner during the Fall '10 term at UC Irvine.

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Workshop 5 Key-1 - Workshop #5 Chem 1A Fall 2010 1. The...

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