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Unformatted text preview: C C C C C H H H H H H H H H H becomes C C C C C Since you know C always (essentially) has 4 bonds and you know that any element other than H must be explicitly shown, you can determine the number of H atoms bound to each C. The leftmost H already has two bonds, so it must also have two H atoms bound to it. The secondtoleft H already has three bonds, so it must have one H bound to it. And so on. 3. Since there are a huge number of Ccontaining compounds, we can save even more time by not having to write the C for carbon every time it appears in a structure. Hence: C C C C C becomes where each end of a line and each intersection are understood to be a C atom. H O H...
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 Spring '09
 campion
 Chemistry, Electron

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