solution_pdf2

# solution_pdf2 - billing (cab4763) HW 1 Opyrchal (11109) 1...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: billing (cab4763) HW 1 Opyrchal (11109) 1 This print-out should have 9 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points A basketball player is 5 ft 11 5 8 in tall. What is his height in centimeters? Correct answer: 181 . 928 cm. Explanation: We can convert to inches and then to cen- timeters: 5 ft 11 5 8 in = parenleftbigg 5 ft 12 in 1 ft + 11 . 625 in parenrightbigg 2 . 54 cm 1 in = 181 . 928 cm . 002 10.0 points For the given triangles, a = 10 . 6 m, b = 7 . 4 m, and = 50 . 8 . a b Find . Correct answer: 34 . 7061 . Explanation: Let the common side be x . a b x In the triangle on the left, tan = x a x = a tan , and in the triangle on the right, sin = b x = b a tan = arcsin parenleftbigg b a tan parenrightbigg = arcsin bracketleftbigg 7 . 4 m (10 . 6 m) tan 50 . 8 bracketrightbigg = 34 . 7061 . 003 10.0 points A person walks 25 m East and then walks 32 m at an angle 38 North of East. What is the magnitude of the total dis- placement? Correct answer: 53 . 9427 m. Explanation: Let : R a = 25 m , R b = 32 m , and = 38 . The total displacement is the vector sum of the two displacements, so R x = R a + R b cos = 25 m + (32 m) cos38 = 50 . 2163 m and R y = R...
View Full Document

## This note was uploaded on 11/23/2010 for the course PHYS PHYS111 taught by Professor Gayen during the Spring '10 term at NJIT.

### Page1 / 4

solution_pdf2 - billing (cab4763) HW 1 Opyrchal (11109) 1...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online